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Question

The wavelength of radiation is λ0 When an electron jumps from third to second orbit of hydrogen atom. For the electron to jump from the fourth to the second orbit of the hydrogen atom, the wavelength of radiation emitted will be

A
1625λ0
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B
2027λ0
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C
2720λ0
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D
2516λ0
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Solution

The correct option is B 2027λ0
1λ=R(1n211222)
1λ0=R(122132)=R(1419)=5R36
1λ=R(122142)=R(14116)=3R16
λλ0=536×163=2027

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