Question

The weight of 112 ml of oxygen at STP, on liquifaction would be:

• A. 0.32 g
• B. 0.64 g
• C. 0.16 g
• D. 0.96 g

Answer 1

Answer: (C)

0.16 g

$22.4L$ of oxygen at NTP weight $32g$
$112\times 10^{-3}L$ of oxygen at NTP weights $112\times 10^{-3}\times$ $\frac{32}{22.4}$ $=0.16g$
conclusion: Weight of 112ml of oxygen at NTP on liquification would be $0.16g$