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Archimedes' Principle

The weight of...

Question

The weight of a block in air is measured by using a spring balance and it is [see fig (a)]. Now, it is completely immersed in water. Now, the reading of the weight of the block in the water as shown by the spring balance is $4.5 N$ . The buoyant force acting on the block is

A

5 N

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B

0.5 N

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C

4.5 N

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D

1 N

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Solution

The correct option is A $0.5 N$
When a body is partly or completely immersed in water (or any other liquid), then:
Loss in weight of body = Weight of water (liquid) displaced by the body = Buoyant force or upthrust exerted by water (any liquid) on the body.
In this case, the weight of the block in air is $5 N$ and the weight of the block in water is $4.5 N$ .
The loss in weight of the body $= 0.5 N =$ Buoyant force.
Hence, the buoyant force acting on the block is 0.5 N.

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