wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The weight of a fuel pump is 3 kg 150 g. If the pump is made of 21 identical parts, the weight of each part in grams will be ____.

A
140 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
150 g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
160 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
170 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 150 g
You know,
1 kg = 1000 gm.


So, 3 kg will be:
=3×1000=3000 g.

Weight of the pump = 3kg 150g.
Converting the entire weight into grams,
3 kg 150 g = 3000 gm+150 g=3150 g.

Now, the pump is made of 21 identical parts.

So, the weight of each part in grams will be equal to:
3150÷21.

Calculating 3150÷21 by box method of divsion,


Adding the partial quotients, the final quotient as:
100+40+10=150.

Hence, the weight of each part of the pump will be 150 g.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Playing with 2 - Digit and 3 - Digit Numbers
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon