Question

The weight of a man standing in a lift becomes eleven tenth of his actual weight when the lift is accelerated upwards. His weight becomes four fifth of his actual weight when the lift accelerate downwards. find the ratio of his weight in the lift

Answer 1

$$\begin{gathered} \text{The ratio is} \\ \text{Normal weight: weight while going up: weight while going down} \\ =1:\frac{11}{10}:\frac{4}{5}=10:11:8 \end{gathered}$$