The weight of an object at the centre of the earth of radius R is

zero

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infinite

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R

times the weight at the surface of the earth

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1 / R^{2}

times the weight at surface of the earth

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Solution

The correct option is A zero
The weight of the body at the surface of the earth is equal to zero. The accelertion due to gravity is maximum on the surface of the earth and as we towards the centre of the equator it becomes zero.
The acceleration due to gravity varies due to the shape of the earth. The radius of the earth is more at the equator than at the poles.
Thus, the value of g at the centre of the earth is zero.

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Similar questions

The weight of an object at the centre of the earth of radius R is :
(a) zero
(b) R times the weight at the surface of the earth
(c) infinite
(d) $1 / R^{2}$ times the weight at the surface of the earth

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