The weight of an object in air is $16 N$ . It weighs $12 N$ when fully immersed in water. The weight of water displaced by the object is

12 N

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4 N

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16 N

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14 N

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Solution

The correct option is B $4 N$
Answer is B.
Archimedes' principle indicates that the upward buoyant force that is exerted on a body immersed in a fluid, whether fully or partially submerged, is equal to the weight of the fluid that the body displaces.
In this case, The weight of an object in air is $16 N$ and it weighs $12 N$ when fully immersed in water. So, the weight of the water displaced is given as $16 N - 12 N = 4 N$ .
Therefore, the weight of water displaced by the object is 4 N.

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The weight of an object in air is 16N. It weighs 12N when fully immersed in water. The weight of water displaced by the object is

The weight of an object in air is $16 N$ . It weighs $12 N$ when fully immersed in water. The weight of water displaced by the object is