The weight of any person on the moon is about $1 / 6$ times that on the earth. He can lift a mass of $15 k g$ on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

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Solution

Step 1: Given that:
The weight of the person on earth is six times that on the moon
$W_{m o o n} = \frac{W_{e a r t h}}{6}$ $W = w e i g h t$
Mass that the person can lift on earth -
$m_{e a r t h} = 15 k g$
Step 2: Formula used:
$W = m g F = m g$ $g = a c c e l e r a t i o n d u e t o g r a v i t y o n t h a t p l a n e t$ , $F = f o r c e a p p l i e d t o l i f t t h e o b j e c t$
Step 3: Calculating the height of the jump on planet A:
Finding the relation between acceleration due to gravity on earth and the moon -
$W_{m o o n} = \frac{W_{e a r t h}}{6} m g_{m o o n} = \frac{m g_{e a r t h}}{6} \frac{g_{e a r t h}}{g_{m o o n}} = 6$
Finding the maximum mass that the person can lift on the moon -
$F_{e a r t h} = F_{m o o n} m_{e a r t h} g_{e a r t h} = m_{m o o n} g_{m o o n} m_{e a r t h} \frac{g_{e a r t h}}{g_{m o o n}} = m_{m o o n} m_{_{m o o n}} = m_{e a r t h} \times 6 m_{_{m o o n}} = 15 \times 6 m_{_{m o o n}} = 90 k g$
Hence, the person can lift up to $90 k g$ on the moon.

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The weight of any person on the moon is about 1/6 times that on the earth. He can lift a mass of 15kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

The weight of any person on the moon is about $1 / 6$ times that on the earth. He can lift a mass of $15 k g$ on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?