The weight of chlorine gas undergoing oxidation when excess of chlorine is sent into hot concentrated caustic soda solution containing 24 grams of solute in it 3Cl2+6NaOH→5NaCl+NaClO3+3H2O
A
21.3g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
17.75g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
3.55 g
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
10.65g
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution
The correct option is D 10.65g 3Cl2+6NaOH→5NaCl+NaCl+NaClO3+3H2O 3×71240 half mle of chlorine undergo oxidation i.e. 10.65g