The width of each of nine classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class 10.6. Then the upper-class boundary of the highest class is

35.6

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33.1

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30.6

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28.1

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Solution

The correct option is B
33.1

Width of each class = 2.5

No. of classes = 9

Lower class boundary of the lowest class

= 10.6

$∴$ Upper class limit of highest class

= 10.6 + $9 \times$ 2.5

= 10.6 + 22.5 = 33.1

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The width of each of nine classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class 10.6. Then the upper-class boundary of the highest class is

The correct option is B 33.1 Width of each class = 2.5 No. of classes = 9 Lower class boundary of the lowest class = 10.6 ∴ Upper class limit of highest class = 10.6 + 9× 2.5 = 10.6 + 22.5 = 33.1

The correct option is B
33.1

Width of each class = 2.5

No. of classes = 9

Lower class boundary of the lowest class

= 10.6

$∴$ Upper class limit of highest class

= 10.6 + $9 \times$ 2.5

= 10.6 + 22.5 = 33.1