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Question

The work done by 200 calorie of heat in isothermal expansion of ideal gas is:

A
836.8 J
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B
418.4 J
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C
555.2 J
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D
664.5 J
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Solution

The correct option is A 836.8 J
From first law of thermodynamics
U=q+w

Here, U=0, since process is isothermal.
q=w
w=200 cal

So work done will be 200 calorie
Again,
1 cal=4.184 J
So work done = 200×4.184 J=836.8 J

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