The work done by a person in carrying a box of mass 10 kg from bottom to the top of a friction less inclined plane 5m long and 3 m high is $(g = 9.8 m / s e c^{2})$ -

392 L

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294 L

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98 L

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0.98 L

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Solution

The correct option is B 294 L
In this total work done was equal to work against the gravity
W=mgH
$W = 10 \times 9.8 \times 3 = 294 J$
Hence the correct option is B

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