The work done by friction when force acting is 2N and displacement of body 100m is::

200 J

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- 200 J

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600 J

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- 600 J

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Solution

The correct option is A $- 200 J$
The frictional force and the displacement are in the opposite direction, therefore the angle between frictional force and displacement is $θ = 180^{\circ}$ .
Thus, work done by the friction is
$W_{f} = f d cos 180^{\circ}$
$= (2 N) (100 m) cos 180^{\circ} = - 200 J$ .

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doubles its kinetic energy to

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. The displacement of the body during this interval is:

When a force acting on a body displaces it in the direction of force, the work done by the force is

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The work done by friction when force acting is 2N and displacement of body 100m is::

The correct option is A −200 JThe frictional force and the displacement are in the opposite direction, therefore the angle between frictional force and displacement is θ=180∘.Thus, work done by the friction isWf=fd cos180∘=(2N)(100m)cos180∘=−200 J.