The work done by the force (4,−2,3) to move a particle along a straight line from the point A(3,3,−1) to B(6,4,−2) is
A
3 units
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B
5 units
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C
7 units
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D
9 units
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Solution
The correct option is C 7 units We know that work done by given force is calculated as W=−→F.→S So first calculating the vector S, which can be calculated as
→S=(→B−→A)⇒→S=(6−3)ˆi+(4−3)ˆj+(−2−(−1))ˆk⇒→S=3ˆi+ˆj−ˆk W=−→F.→S=(4ˆi−2ˆj+3ˆk).(3ˆi+ˆj−ˆk)=7units So, option C is correct answer.