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Question

The work done in joules in increasing the extension of a spring of stiffness 10 N/cm from 4 cm to 6 cm.

A
1
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B
10
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C
50
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D
100
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Solution

The correct option is A 1
Given Spring stiffness K=10N/cm=1000N/m, Initial Position x1=4cm=0.04m, Final position x2=6cm=0.06m
Work done by spring =12K(x22x21)
Work done=12×1000×(0.0620.042)=1.0J

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