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Work

The work done...

Question

The work done in sliding a wooden box of mass $5 k g$ along a friction less inclined plane of inclination $30^{o}$ and length $10 m$ is______ $J$ . $(g = 10 {m s}^{- 2})$

500

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250

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125

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1500

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Solution

The correct option is C $250$
Work done=force×distance
W=mg $s i n 30 ° \times l$
W= $50 \times \frac{1}{2} \times 10 = 250 J$

Suggest Corrections

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