Question

# The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?

Solution

## Work function of the metal is $$4.2\ eV;$$Given: $$\lambda=330nm$$.The energy of incident photon is given by,$$E=hc/\lambda$$$$E = \dfrac{6.63\times 10^{-34}\times 3\times 10^8}{330\times 10^{-9}}$$$$E =6\times10^{-19}J\ or\ 3.79eV$$E is less than work function.Hence, no photoelectric emission will take place.PhysicsNCERTStandard XII

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