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Question

The work function for a certain metal is 4.2 eV. Will this metal give photoelectric emission for incident radiation of wavelength 330 nm?


Solution

Work function of the metal is $$4.2\ eV;$$

Given: $$ \lambda=330nm$$.

The energy of incident photon is given by,
$$E=hc/\lambda$$

$$E = \dfrac{6.63\times 10^{-34}\times 3\times 10^8}{330\times 10^{-9}}$$

$$E =6\times10^{-19}J\ or\ 3.79eV$$

E is less than work function.
Hence, no photoelectric emission will take place.

Physics
NCERT
Standard XII

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