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Question
The work function of a certain metal is 3.31×10−19J. Then, the maximum kinetic energy of photoelectrons emitted by incident radiation of wavelength 5000 A is
(Givenh=6.62×10−34J−s,c=3×10−8ms−1,e=1.6×10−19C)
The work function of a certain metal is 3.31×10−19J. Then, the maximum kinetic energy of photoelectrons emitted by incident radiation of wavelength 5000 A is
(Givenh=6.62×10−34J−s,c=3×10−8ms−1,e=1.6×10−19C)
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Solution
The correct option is B 0.41eV
Work function W0=3.31×10−19J
Wavelength of incident radiation
λ=5000×10−10m
E=W0+KE
(According to Einstein equation)
hcλ3.31×10−19+KE
KE=−3.31×10−19+6.62×10−34×3×1085000×1010
=−3.31×10−19+10−19+6.62×35×10−19
=(−3.31×1.324×3)×10−19
=(3.972−3.31)×10−19=0.662×10−19J
⇒E=0.662×10191.6×10−19=0.41eV
Work function W0=3.31×10−19J
Wavelength of incident radiation
λ=5000×10−10m
E=W0+KE
(According to Einstein equation)
hcλ3.31×10−19+KE
KE=−3.31×10−19+6.62×10−34×3×1085000×1010
=−3.31×10−19+10−19+6.62×35×10−19
=(−3.31×1.324×3)×10−19
=(3.972−3.31)×10−19=0.662×10−19J
⇒E=0.662×10191.6×10−19=0.41eV
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