Question

The work function of a metal is X eV. When light of energy 2X is made incident on it then the maximum kinetic energy of emitted photoelectron will be

• A. $2.5XeV$
• B. $2XeV$
• C. $XeV$
• D. $3XeV$

Answer 1

The correct option is C $XeV$

The maximum kinetic energy of emitted photoelectron is given as
$E_{max}=h\nu -\varphi$
where,$\nu$ is the frequency of incident light and $\varphi$ is photoelectric work function of metal.
$E_{max}=2X-X$ ...................(given)
$E_{max}=XeV$

So, the answer is option (C).