The work function of a photoelectric material is 3.3 eV. The threshold frequency will be equal to

$8 \times 10^{4} H z$

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$8 \times 10^{56} H z$

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$8 \times 10^{10} H z$

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$8 \times 10^{14} H z$

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Solution

The correct option is D
$8 \times 10^{14} H z$

$v_{0} = \frac{W_{0}}{h} = \frac{3.3 \times 1.6 \times 10^{- 19}}{6.6 \times 10^{- 34}} = 8 \times 10^{14} H z$

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The work function of a photoelectric material is 3.3 eV. The threshold frequency will be equal to

The correct option is D 8×1014Hz v0=W0h=3.3×1.6×10−196.6×10−34=8×1014Hz

The correct option is D
$8 \times 10^{14} H z$

$v_{0} = \frac{W_{0}}{h} = \frac{3.3 \times 1.6 \times 10^{- 19}}{6.6 \times 10^{- 34}} = 8 \times 10^{14} H z$