Question

The $X-X$ bond length is $1.00$$\mathring{A}$ and $C-C$ bond length is $1.54$ $\mathring{A}$. If electronegativities of '$X$' and '$C$' are $3.0$ and $2.0$ respectively, the $C-X$ bond length is likely to be:

• A. $1.27$ $\mathring{A}$
• B. $1.18$ $\mathring{A}$
• C. $1.08$ $\mathring{A}$
• D. $1.28$ $\mathring{A}$

Answer 1

The correct option is B $1.18$ $\mathring{A}$

$C-X=r_c+r_X-0.09({\chi }_C-{\chi }_X)=\frac{1.54+1}{2}-0.09(3-2)=1.18A^o$

Thus, $C-X$ bond length is $1.18A^0$.