Question

The young's duble slit experiment is performed with blue and green light of wavelength $4360\mathring{A}$ and $5460\mathring{A}$ respectively. if $x$ is the distance of $4th$ maxima from central one, then

• A. $x\left(blue\right)=x\left(green\right)$
• B. $x\left(blue\right)>x\left(green\right)$
• C. $x\left(blue\right)<x\left(green\right)$
• D. $\frac{x\left(blue\right)}{x\left(green\right)}=\frac{5460}{4360}$

Answer 1

The correct option is C $x\left(blue\right)<x\left(green\right)$

Given that,

Wave length of blue light ${\lambda }_B=4360\stackrel{\circ }{A}$

Wave length of green light ${\lambda }_G=5460\stackrel{\circ }{A}$

$n=4$

In the young's duble slit experiment

$x=n\lambda \frac{D}{d}$

For fourth maxima n = 4

$\frac{x_B}{x_G}=\frac{{\lambda }_B}{{\lambda }_G}=\frac{4360}{5460}$

$\frac{x_B}{x_G}<1$

$x_B<x_G$

This is the answer