Question

The zeroes of the polynomial $f\left(x\right)=x^2-3$ are $x=$

• A. $3,-3$
• B. $\sqrt{3},-\sqrt{3}$
• C. $3,-\sqrt{3}$

Answer 1

The correct option is B $\sqrt{3},-\sqrt{3}$

Given: $f\left(x\right)=x^2-3$
Now, for finding the zeroes of the polynomial, we equate the function $f\left(x\right)=0$
$\Rightarrow x^2-3=0\Rightarrow x^2=3\Rightarrow x=\pm \sqrt{3}$