The zeroes of the polynomial
$P (x) = a x^{2} + b x + c$ are 1 and 2.
Find the value of $a, b and c$ .

a = 1, b = -3 , c = 1

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a = 1 , b = -3, c = 2

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a = 3, b = -1, c = 1

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a = -1 , b = -3, c = -2

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Solution

The correct option is B
a = 1 , b = -3, c = 2

Given the zeroes of $P (x)$ are 1 and 2.
$⟹ P (x) = (x - 1) (x - 2)$
$⟹ a x^{2} + b x + c = x^{2} - 3 x + 2$
$⟹ a = 1, b = - 3, and c = 2$

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