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Question

The zeros of the quadratic polynomial x2+88x+125 are

(a) both positive (b) both negative

(c) one positive and one negative (d) both equal

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Solution

We know that,
In a quadratic expression ax2+bx+c=0 If a, b, c will have the same sign, then both zeroes of the expression are negative
Compare given expression
x2+88x+125 with ax2+bx+c
a = 1 , b = 88 ,c = 125
All are positive sign,
Therefore, the for expression, both zeroes has a negative sign.
Option B ) is correct.

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