Question

The zeros of the quadratic polynomial x² + 88x + 125 are

(a) both positive
(b) both negative
(c) one positive and one negative
(d) both equal

Answer 1

$$\begin{gathered} \left(\text{b}\right)\mathrm{both}\mathrm{negative} \\ \text{Let}\alpha \text{and}\beta \text{be the zeroes of}{x}^2+88x+125. \\ \text{Then}\alpha \text{+}\beta \text{=}-88\text{and}\alpha \times \beta \text{=125} \\ \text{This can only happen when both the zeroes are negative}. \end{gathered}$$