Say: There has been a theft and some jewels have gone missing.
The information we have about it is:
From 503 jewels, the number of jewels has become this number:
(i) The face value at Hundreds place is decreased by 2.
(ii) The place value at Tens place is now 6 Tens.
(iii) The face value at Ones place remains the same.
Steps:
\(\bullet\) Let us do it on the whiteboard.
\(\bullet\) Originally, there were 503 jewels. There are 5 Hundreds, 0 Tens and 3 Ones. The face values are: 5 at Hundreds place, 0 at Tens place, and 3 at Ones place.
\(\bullet\) After the theft, the face value at Hundreds place was decreased by 2.
\(\bullet\) That means, 5 – 2 = 3.
\(\bullet\) The place value at Tens place is now 6 Tens. If we write 6 at Tens place, the digit or the face value in the Tens place will be 6.
\(\bullet\) The face value at Ones place remains the same, i.e., it remains 3.
\(\bullet\) So, the new count is 363.
\(\bullet\) To find the number of stolen jewels, we will have to do: 503 – 363 = 140.
\(\bullet\) Thus, the new count is 363 and stolen ones are 140.
\(\bullet\) Hence, option A is the correct answer.