Question

Then the distance from the thrower to the point where the ball returns to the same level is

• A. 58 m
• B. 68 m
• C. 78 m
• D. 88 m

Answer 1

The correct option is C 78 m

given data,

$u=30m{s}^{-1}$

$\theta ={30}^0$

$g=10m{s}^{-2}$

The distance from the thrower to the point where the ball returns to the same level is
$R=\frac{u^{2}sin2\theta }{g}$

$=\frac{(30m{s}^{-1}{)}^{2}sin{60}^{\circ }}{10m{s}^{-2}}$

$=\frac{(30{)}^2\times \frac{\sqrt{3}}{2}}{10}$

$=78m$