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Question

There are 1 mole of atoms of an element A. When half of the atoms transfer one electron to another atom, 405 kJmol1 of energy was found to be consumed. An additional energy of 745 kJ/mol was further required to convert all the A ions to A+. Calculate the ionisation energy of atom A in kJ

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Solution

(AA+);ΔHIE=x kJ/mol
(A+eA);ΔHeg=y kJ/mol
Let x and y be IE and ΔHeg respectively.
12(x+y)=405kJ
12(xy)=745kJ
On solving, we get,
x = 1150 kJ and y = -340 kJ




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