There are $10$ compartments in passenger train carries on average $15$ passengers per compartment. If atleast $15$ passengers were sitting in each compartment, no any compartment has equal no of passengers , and any compartment does not exceed the number of average passengers except $10^{t h}$ compartment.Find how many passengers can be accommodated in $10^{t h}$ compartment ?

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Solution

No of passengers $= 15 \times 10 = 150$
$15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 = 99$
$150 - 99 = 51$

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No of passengers =15×10=15015+14+13+12+11+10+9+8+7=99150−99=51

No of passengers $= 15 \times 10 = 150$
$15 + 14 + 13 + 12 + 11 + 10 + 9 + 8 + 7 = 99$
$150 - 99 = 51$