Question

There are 156, 208 and 260 students in groups A,B and C, respectively. Buses are to be hired to take them for a field trip. Find the minimum number of buses to be hired, if the same number of students should be accommodated in each bus.

Answer 1

You should take HCF of 156, 208 and 206

H.C.F of 156, 208

P.F of 156 = 2 x 2 x 3 x 13
P.F of 208 = 2 x 2 x 2 x 2 x 13
Therefore H.C.F of 156, 208 = 2 x 2 x 13 = 52.

Now, H.C.F of 52 and 260

P.F of 52 = 2 x 2 x 13
P.F of 260 = 2 x 2 x 5 x 13

H.C.F = 2 x 2 x 13 = 52
Max. number of students per bus = 52

Total number of students = 156 + 208 + 260 = 624 students.

No. of buses = 624 / 52 = 12 buses