Question

There are 16 squares in the dihybrid cross of RrYy. How many different types of genotypes and phenotypes are formed? Note them down in the format given. $\begin{array}{ccc}\text{S.No.}& \text{Genotype found in F1}& \text{Their expected Phenotypes}\\ & & \end{array}$

Answer 1

Part 1: Dihybrid cross RrYy x RrYy

The possible gametes of each parent are: RY, Ry, rY and ry

The results of the cross is given below:
Part 2: Phenotype and genotype of F1 generation offsprings

The given table will be as follows:
$\begin{array}{ccc}\text{S.No.}& \text{Genotype found in F1}& \text{Their expected Phenotypes}\\ \text{1}& \text{RRYY - 1}& \text{Round and yellow}\\ \text{2}& \text{RRYy -2}& \text{Round and yellow}\\ \text{3}& \text{RRyy-1}& \text{Round and green}\\ \text{4}& \text{RrYY-2}& \text{Round and yellow}\\ \text{5}& \text{RrYy-4}& \text{Round and yellow}\\ \text{6}& \text{Rryy-2}& \text{Round and green}\\ \text{7}& \text{rrYY-1}& \text{Wrinkled and yellow}\\ \text{8}& \text{rrYy-2}& \text{Wrinkled and yellow}\\ \text{9}& \text{rryy-1}& \text{Wrinkled and green}\end{array}$
As visible in the table there are 9 types of genotypes and 4 types of phenotypes possible in the ratio given below:
Genotypic ratio = 1:2:1:2:4:2:1:2:1
Phenotypic ratio = 9:3:3:1