There are 3 red and 4 blue marbles in a bag. At random, one marble is drawn. The probability that the marble drawn is blue:

1

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\frac{3}{7}

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\frac{4}{7}

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\frac{2}{7}

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Solution

The correct option is C $\frac{4}{7}$
The number of favourable outcomes of getting blue marbles = 4
Probability $= \frac{4}{7}$

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