Question

There are 30 apples in a bucket.

What is/are the correct way(s) of distributing it among 2 children so that both of them get equal number of apples?

• A. Each child gets: $(20÷2)+(10÷2)$ apples
• B. Each child gets: $(30÷2)$ apples
• C. Each child gets: $(30÷3)$ apples
• D. Each child gets: $(10÷2)+(10÷2)+(10÷2)$ apples

Answer 1

Answer: (A), (B), (D)

The correct options are
A Each child gets: $(20÷2)+(10÷2)$ apples
B Each child gets: $(30÷2)$ apples
D Each child gets: $(10÷2)+(10÷2)+(10÷2)$ apples

According to the question:

• There are 30 apples
• It is to be divided equally among 2 children

We can make different groups of these apples to divide them among the 2 children.

$\ast \text{1st group}:$ (20 apples + 10 apples)
We divide first 20 apples among 2 children which is
20$÷$2 = 10 apples each.
So, 30 - 20 = 10 apples are remaining.
These 10 apples are again to be divided among the 2 children which is
10$÷$ 2 = 5 apples each.
$\therefore$ Each child gets 10 + 5 = 15 apples.

$\ast \text{2nd group}:$ (full 30 apples)
We have to divide 30 apples among 2 children which is:
30$÷$2 = 15 apples each.
$\therefore$ Each child gets 15 apples.

$\ast \text{3rd group}:$ (10 apples + 10 apples + 10 apples)
If we divide first 10 apples among 2 children which is:
10$÷$2 = 5 apples each.
Similarly, we repeat this process for the next two bunches of 10 apples each.
So, each child gets 5 + 5 + 5 = 15 apples.

So, we see that all these ways of distribution can be used to divide 30 apples among 2 children and at the end each child gets 15 apples.
Also, if any group fails to give 15 apples to each child then that group formation is not correct.