There are 32, 48 and 56 students in class V, class VI and class VII,respectively. Find the maximum number of students who can stand in a row, if each row has the same number of students and also find the number of rows formed.

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Solution

The number of students in each row $=$ $H . C . F .$ of $32, 48$ and $56$

$H . C . F .$ of $32, 48, 56$ is $8$

Hence,

The number of students who can stand in a row if each row has an equal number of students is $8$

Then the number of rows in class $V$ $= \frac{32}{8} = 4$

The number of rows in class $V I$ $= \frac{48}{8} = 6$

The number of rows in class $V I I$ $= \frac{56}{8} = 7$

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There are 32, 48 and 56 students in class V, class VI and class VII,respectively. Find the maximum number of students who can stand in a row, if each row has the same number of students and also find the number of rows formed.

The number of students in each row = H.C.F. of 32,48 and 56H.C.F. of 32,48,56 is 8Hence,The number of students who can stand in a row if each row has an equal number of students is 8Then the number of rows in class V =328=4The number of rows in class VI =488=6The number of rows in class VII =568=7