There are 40 passengers in a bus. Some have tickets worth ₹ 3 and remaining worth ₹ 10. The total collection from these passengers is ₹ 295. Find how many passengers have tickets worth ₹ 3.

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Solution

The correct option is C 15
$Let the number of passengers having ticket worth ₹ 3 = x$

$Then the passengers having ticket worth ₹10 = 40-x$

Then,
$3 \times x + 10 \times (40 - x) = 295 \Rightarrow 3 x + 400 - 10 x = 295 \Rightarrow - 7 x = 295 - 400 \Rightarrow - 7 x = - 105 \Rightarrow x = \frac{- 105}{- 7} \Rightarrow x = 15$

$∴ Number of passengers with tickets worth ₹3 = 15.$

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There are 40 passengers in a bus. Some have tickets worth ₹ 3 and remaining worth ₹ 10. The total collection from these passengers is ₹ 295. Find how many passengers have tickets worth ₹ 3.

The correct option is C 15Let the number of passengers having ticket worth ₹ 3 = x Then the passengers having ticketworth ₹10 = 40-x Then, 3×x+10×(40–x)=295⇒ 3x+400–10x=295⇒ −7x=295–400⇒ −7x=−105⇒ x=−105−7⇒ x=15 ∴Number of passengers with tickets worth ₹3 = 15.