There are $40$ pieces of building blocks in a bag.
$10$ each of blue, green, red, and yellow.
Two pieces are chosen at random.
Identify the probability that both of the pieces chosen are green.

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Solution

Finding the required probability:
Given,
Total building blocks are $40$
Number of red blocks $=$ Number of green blocks $=$ Number of blue blocks $=$ Number of yellow blocks $=$ $10$
Therefore, the probability of choosing the first green block is,
$P (green) = \frac{Number of green blocks}{Total blocks} = \frac{10}{40}$
When choosing the second green block, the probability is
$\begin{array}{rcl} P (green) & = & \frac{Number of remaining green blocks}{Total remaining blocks} \\ = & \frac{9}{39} \end{array}$
Therefore, the required probability of choosing two green blocks is,
$P (GG) = \frac{10}{40} \times \frac{9}{39} = \frac{3}{52}$
Hence, the probability that both of the pieces chosen are green is $\frac{3}{52}$ .

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There are 40 pieces of building blocks in a bag. 10 each of blue, green, red, and yellow. Two pieces are chosen at random. Identify the probability that both of the pieces chosen are green.

There are $40$ pieces of building blocks in a bag.
$10$ each of blue, green, red, and yellow.
Two pieces are chosen at random.
Identify the probability that both of the pieces chosen are green.