Question

There are 5 different caps $c_1,c_2,c_3,c_{4}and{c}_5$ and 5 different boxes $B_1,B_2,B_3,B_{4}and{B}_5$. The capacity of each box is sufficient to accomodate all the 5 caps.

If $C_{1}and{C}_5$ are similar in all aspects, in how many ways can you arrange the caps in such a way that all the boxes have one cap?

• A. 70
• B. 60
• C. 75
• D. 80

Answer 1

The correct option is B 60

Required numbers of ways $=\frac{5!}{2!}=60$
(since 2 caps are identical)