Question

There are 6 red and 5 black balls in a bag. Two balls are drawn at random one after another with replacement. The probability that both the balls drawn may be red is

• A. $\frac{30}{121}$
• B. $\frac{25}{121}$
• C. $\frac{18}{121}$
• D. $\frac{36}{121}$

Answer 1

The correct option is D $\frac{36}{121}$

$6R+5B$ balls
If two balls are drawn at random one after another with replacement
Probability that both the balls drawn may be red is$=\frac{6}{11}\times \frac{6}{11}=\frac{36}{121}$