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Question

# There are three samples of H2O2 labelled as 10 vol., 15 vol., and 20 vol. Half litre of each sample is mixed and then diluted with equal volumes of water. Calculate the volume strength of the resultant solution.

A
1.339
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B
7.5
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C
5.0
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D
2.68
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Solution

## The correct option is B 7.5Volume strength of H2O2 ​= 5.6×N N of 10 volume H2O2 ​= 105.6 N N of 15 volume H2O2 ​= 155.6 N N of 20 volume H2O2 ​= 205.6 N Since half litre of each sample is mixed, the total volume becomes 1.5 L This mixture is diluted to double its volume. So, 1.5 L×2 =3 L or 3000 mL N×3000=105.6×500+155.6×500+205.6×500 N of H2O2​ mixture = 1.339 N Volume strength of H2O2​= 1.339×5.6 = 7.5

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