THERE ARE TWO ANGLES OF PROJECTION FOR WHICH THE HORIZONTAL RANGE IS THE SAME.PROVE THAT THE SU OF THE MAXIMUM HEIGHTS FOR THESE TWO ANGLES DOES NOT DEPEND UPON THE ANGLE OF PROJECTION

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$f o r s a m e r a n g e t h e a n g l e o f p r o j e c t i o n i s θ a n d 90 - θ . M a x i m u m h e i g h t w h e n p a r t i c l e i s t h r o w n a t a n a n g l e θ i s h_{1} = \frac{u^{2} \sin^{2} θ}{2 g} . . . 1 M a x i m u m h e i g h t w h e n p a r t i c l e i s t h r o w n a t a n a n g l e 90 - θ i s h_{2} = \frac{u^{2} \cos^{2} θ}{2 g} . . 2 h_{1} + h_{2} = \frac{u^{2} \sin^{2} θ}{2 g} + \frac{u^{2} \cos^{2} θ}{2 g} = \frac{u^{2}}{2 g} s o t h e i r s u m i \sin d e p e n d e n t o f a n g l e o f p r o j e c t i o n R e g a r d s$

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