Question

There are two cuboidal boxes as shown in the given figure. Does Box 1 require the less amount of material to make ?

• A. True
• B. False

Answer 1

The correct option is A True

Total surface area of Box 1 $=2(lb+bh+hl)$

$=2(60\times 40+40\times 50+60\times 50)$

$=2(2400+2000+3000)$

$=2\left(7400\right)$

$=14800$ sq. units

Total surface area of Box 2 $=2(lb+bh+hl)$

$=2(50\times 50+50\times 50+50\times 50)$

$=2(2500\times 3)$

$=6\times 2500$

$=15000$ sq. units

As $(TSA{)}_A<(TSA{)}_B$

$\therefore$ Box A requires less material