There are two numbers x and y, If the sum of the smaller number (x) and three the other number is equal to the sum of three times the smaller number and 27. The difference between the numbers is 7. Find the larger number y.

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Solution

The correct option is C 13
y = x + 7
x+3(x+7) = 3x + 27 $\Rightarrow$ 4x + 21 = 3x+27
$\Rightarrow$ x =6
So, y = x + 7 = 6 + 7 = 13

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There are two numbers x and y, If the sum of the smaller number (x) and three the other number is equal to the sum of three times the smaller number and 27. The difference between the numbers is 7. Find the larger number y.

The correct option is C 13y = x + 7 x+3(x+7) = 3x + 27 ⇒ 4x + 21 = 3x+27 ⇒ x =6 So, y = x + 7 = 6 + 7 = 13

The correct option is C 13
y = x + 7
x+3(x+7) = 3x + 27 $\Rightarrow$ 4x + 21 = 3x+27
$\Rightarrow$ x =6
So, y = x + 7 = 6 + 7 = 13