Question

There are two types of grass, green and pink. One cow eats green grass and the other eats pink grass. The region covered is as shown. Which cow ate more grass? (Units given here are in feet.)

• A. Cow that ate green grass.
• B. Cow that ate pink grass
• C. Both the cow ate equally.

Answer 1

The correct option is B Cow that ate pink grass

Let's mark the areas as shown in below figure,
Now, let's find the areas of each part one by one:

As we know, a square has area $={\text{side}}^2$

Also, Area of a triangle
$=\frac{1}{2}\times \text{Base}\times \text{Height}$

Now, Let's calculate the area covered in green, i.e. $I+II$

Area $I=\frac{1}{2}\times 4\times 3=6$ sq. units.

Area $II=\frac{1}{2}\times 4\times (10-4)=12$ sq. units.

$\therefore \text{Area}I+\text{Area}II=12+6=18$ sq. units.

Area covered by green grass $=18$ sq. units.

Similarly, let's calculate the area of $III\&IV$

Now, $\text{Area of}III=\frac{1}{2}\times 3\times (10-4)=9$ sq. units

And, $\text{Area of}IV=4\times 4=16$ sq. units

$\Rightarrow \text{Area}III+\text{Area}IV$

$=9+16=25$ sq. units.

Area covered by pink grass $=25$ sq. units

$\therefore$ Area covered in pink grass is greater and hence, the cow eating grass in pink will consume more.