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Question

There are two types of jar. In the 1st jar the ratio of copper and aluminium is 1:2 and in the 2nd Jar is 1: 4. In what ratio these two jar should be mix to make 3rd jar In which the ratio of copper & aluminium become 1:3?

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Solution

Let the required ratio of first to second type be 1:x
According to question 1×13+x×151×23+x×45=13
On solving we get x=53
So required ratio of first to second type = 3:5

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