There exists a uniform electric field E=4×105Vm−1 directed along negative x-axis. A charge of is placed −200μC at the origin, and a charge +200μC of is placed at (3m,0). Find the electrostatic potential energy of the dipole system.
Step 1, Given data
Electric field,E=4×105Vm−1
Charges = −200μCand+200μC
Step 2, Finding the electrostatic potential energy
We know,
The potential energy of the dipole is given by ,−pEcosθ
Here, p=q×d=200×10−6×3=6×10−4
And, E=4×105Vm−1
Putting all the values in the equation
U=−pEcosθ=−6×10−4×4×105cos180o=240J
Hence the potential energy of the system is 240 J