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Question

There is a 5 Ω resistance in an ac circuit. Inductance of 0.1 H is connected with it in series. If equation of ac e.m.f. is 5 sin 50 t then the phase difference between current and e.m.f. is

A
π2
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B
π6
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C
π4
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D
Zero
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Solution

The correct option is C π4
Given,
R=5ΩL=0.1HE=5sin50t

Here, ω=50
XL=ωL=50×0.1=5Ω

sinθ=XLZ

Z=52+52=52Ω

sinθ=552

sinθ=12=sinπ4θ=π4

Correct option is C

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