Question

There is a lamp and a resistor whose resistance are 18 and 6 ohms respectively, while the battery is 6 volt connected in series. Find the total resistance ,current flowing in the circuit ,potential difference across the lamp and resistor.

Answer 1

$$\begin{gathered} \text{Total resistance is}18+6=24\text{ohm} \\ \text{Current flowing in the circuit is}\frac{6}{24}=0.25\text{A} \\ \text{Potential difference across the lamp is}18\times 0.25=4.5\text{V} \\ \text{Potential difference across the resistance is}6\times 0.25=1.5\text{V} \end{gathered}$$