There is a pyramid on a base which is a regular hexagon of side 2a. If every slant edge of this pyramid is of length (5a)2 then the volume of this pyramid must be:
A
3a3
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B
3a3√2
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C
3a3√3
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D
6a3
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Solution
The correct option is C3a3√3 Volumeofthepyramid=√32(2a)2h(h:pyramidheight) h2+(2a)2=(5a2)2 h=3a2 Volumeofthepyramid=3√3a3