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Question

There is a temperature at which the reading on the kelvin scale is numerically


A

equal to that on the celsius scale

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B

lower than that on the celsius scale

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C

less than zero

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D

equal to that on the Fahrenheit scale

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Solution

The correct option is D

equal to that on the Fahrenheit scale


Step 1: Recall conversion relations-

  1. Assume, there is a substance A. We use it to measure the temperature of the substance in Celsius, Fahrenheit, and Kelvin scales.
  2. Let, TC, TF, TK are the temperature of A on the Celsius, Fahrenheit, and Kelvin scale respectively.
  3. According to the conversion formula TF=95TC+32TK=TC+273.15

Step 2: Analyse the conversion relations-

  1. We can see from the conversion relations, that the temperature of the substance A will never be such that the Kelvin scale reading is equal to or less than that on the Celsius scale.
  2. The conversion relations can be rewritten as:
  3. TF=95TK-273.15+325TF=9TK-2298.35
  4. Let, the temperature of the substance A be such that, the temperature reading on Fahrenheit and Kelvin scale is the same.
  5. Therefore, TF=TK=T(say)
  6. Using the conversion relation:
  7. 5T=9T-2298.354T=2298.35T=574.59K
  8. Hence, at temperature, 574.59K the reading on the Fahrenheit scale and Kelvin scale are the same.
  9. Thus, the correct option is (d).

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